Whakaoti i te y^2=4

$${ y }^{ 2 } =4$$

Whakaoti mō y

$$y=2$$

$$y=-2$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tangohia te 4 mai i ngā taha e rua.

$$y^{2}-4=0$$

Whakaarohia te y^{2}-4. Tuhia anō te y^{2}-4 hei y^{2}-2^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(y-2\right)\left(y+2\right)=0$$

Hei kimi otinga whārite, me whakaoti te y-2=0 me te y+2=0.

$$y=2 y=-2$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$y=2 y=-2$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 4 mai i ngā taha e rua.

$$y^{2}-4=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -4 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\left(-4\right)}}{2}$$

Pūrua 0.

$$y=\frac{0±\sqrt{-4\left(-4\right)}}{2}$$

Whakareatia -4 ki te -4.

$$y=\frac{0±\sqrt{16}}{2}$$

Tuhia te pūtakerua o te 16.

$$y=\frac{0±4}{2}$$

Nā, me whakaoti te whārite y=\frac{0±4}{2} ina he tāpiri te ±. Whakawehe 4 ki te 2.

$$y=2$$

Nā, me whakaoti te whārite y=\frac{0±4}{2} ina he tango te ±. Whakawehe -4 ki te 2.

$$y=-2$$

Kua oti te whārite te whakatau.

$$y=2 y=-2$$