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Whakaoti mō x (complex solution)
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Whakaoti mō x
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t^{2}-8t-4=0
Whakakapia te t mō te x^{2}.
t=\frac{-\left(-8\right)±\sqrt{\left(-8\right)^{2}-4\times 1\left(-4\right)}}{2}
Ka taea ngā whārite katoa o te momo ax^{2}+bx+c=0 te whakaoti mā te ture pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Whakakapia te 1 mō te a, te -8 mō te b, me te -4 mō te c i te ture pūrua.
t=\frac{8±4\sqrt{5}}{2}
Mahia ngā tātaitai.
t=2\sqrt{5}+4 t=4-2\sqrt{5}
Whakaotia te whārite t=\frac{8±4\sqrt{5}}{2} ina he tōrunga te ±, ina he tōraro te ±.
x=-\sqrt{2\sqrt{5}+4} x=\sqrt{2\sqrt{5}+4} x=-i\sqrt{-\left(4-2\sqrt{5}\right)} x=i\sqrt{-\left(4-2\sqrt{5}\right)}
I te mea ko x=t^{2}, ka riro ngā otinga mā te arotake i te x=±\sqrt{t} mō ia t.
t^{2}-8t-4=0
Whakakapia te t mō te x^{2}.
t=\frac{-\left(-8\right)±\sqrt{\left(-8\right)^{2}-4\times 1\left(-4\right)}}{2}
Ka taea ngā whārite katoa o te momo ax^{2}+bx+c=0 te whakaoti mā te ture pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Whakakapia te 1 mō te a, te -8 mō te b, me te -4 mō te c i te ture pūrua.
t=\frac{8±4\sqrt{5}}{2}
Mahia ngā tātaitai.
t=2\sqrt{5}+4 t=4-2\sqrt{5}
Whakaotia te whārite t=\frac{8±4\sqrt{5}}{2} ina he tōrunga te ±, ina he tōraro te ±.
x=\frac{\sqrt{8\sqrt{5}+16}}{2} x=-\frac{\sqrt{8\sqrt{5}+16}}{2}
I te mea ko x=t^{2}, ka riro ngā otinga mā te arotake i te x=±\sqrt{t} mō t tōrunga.