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Whakaoti mō x (complex solution)
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Whakaoti mō x
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t^{2}-t-20=0
Whakakapia te t mō te x^{2}.
t=\frac{-\left(-1\right)±\sqrt{\left(-1\right)^{2}-4\times 1\left(-20\right)}}{2}
Ka taea ngā whārite katoa o te momo ax^{2}+bx+c=0 te whakaoti mā te ture pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Whakakapia te 1 mō te a, te -1 mō te b, me te -20 mō te c i te ture pūrua.
t=\frac{1±9}{2}
Mahia ngā tātaitai.
t=5 t=-4
Whakaotia te whārite t=\frac{1±9}{2} ina he tōrunga te ±, ina he tōraro te ±.
x=-\sqrt{5} x=\sqrt{5} x=-2i x=2i
I te mea ko x=t^{2}, ka riro ngā otinga mā te arotake i te x=±\sqrt{t} mō ia t.
t^{2}-t-20=0
Whakakapia te t mō te x^{2}.
t=\frac{-\left(-1\right)±\sqrt{\left(-1\right)^{2}-4\times 1\left(-20\right)}}{2}
Ka taea ngā whārite katoa o te momo ax^{2}+bx+c=0 te whakaoti mā te ture pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Whakakapia te 1 mō te a, te -1 mō te b, me te -20 mō te c i te ture pūrua.
t=\frac{1±9}{2}
Mahia ngā tātaitai.
t=5 t=-4
Whakaotia te whārite t=\frac{1±9}{2} ina he tōrunga te ±, ina he tōraro te ±.
x=\sqrt{5} x=-\sqrt{5}
I te mea ko x=t^{2}, ka riro ngā otinga mā te arotake i te x=±\sqrt{t} mō t tōrunga.