Whakaoti i te x^3-x^3=50-x/2x-1

$${ x }^{ 3 } - { x }^{ 3 } = \frac{ 50-x }{ 2x-1 }$$

Whakaoti mō x

$$x=50$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki \frac{1}{2} nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te 2x-1.

$$\left(2x-1\right)x^{3}-x^{3}\left(2x-1\right)=50-x$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2x-1 ki te x^{3}.

$$2x^{4}-x^{3}-x^{3}\left(2x-1\right)=50-x$$

Whakamahia te āhuatanga tohatoha hei whakarea te -x^{3} ki te 2x-1.

$$2x^{4}-x^{3}-2x^{4}+x^{3}=50-x$$

Pahekotia te 2x^{4} me -2x^{4}, ka 0.

$$-x^{3}+x^{3}=50-x$$

Pahekotia te -x^{3} me x^{3}, ka 0.

$$0=50-x$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$50-x=0$$

Tangohia te 50 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-x=-50$$

Me whakarea ngā taha e rua ki te -1.

$$x=50$$