Whakaoti i te x^3+1x^3+x^2+x+1x^2+x+1

$${ x }^{ 3 } +1 { x }^{ 3 } + { x }^{ 2 } +x+1 { x }^{ 2 } +x+1$$

Aromātai

$$2x^{3}+2x^{2}+2x+1$$

Ngā Upane Otinga

Pahekotia te x^{3} me 1x^{3}, ka 2x^{3}.

$$2x^{3}+x^{2}+x+1x^{2}+x+1$$

Pahekotia te x^{2} me 1x^{2}, ka 2x^{2}.

$$2x^{3}+2x^{2}+x+x+1$$

Pahekotia te x me x, ka 2x.

$$2x^{3}+2x^{2}+2x+1$$

Kimi Pārōnaki e ai ki x

$$6x^{2}+4x+2$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te x^{3} me 1x^{3}, ka 2x^{3}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x^{3}+x^{2}+x+1x^{2}+x+1)$$

Pahekotia te x^{2} me 1x^{2}, ka 2x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x^{3}+2x^{2}+x+x+1)$$

Pahekotia te x me x, ka 2x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x^{3}+2x^{2}+2x+1)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3\times 2x^{3-1}+2\times 2x^{2-1}+2x^{1-1}$$

Whakareatia 3 ki te 2.

$$6x^{3-1}+2\times 2x^{2-1}+2x^{1-1}$$

Tango 1 mai i 3.

$$6x^{2}+2\times 2x^{2-1}+2x^{1-1}$$

Whakareatia 2 ki te 2.

$$6x^{2}+4x^{2-1}+2x^{1-1}$$

Tango 1 mai i 2.

$$6x^{2}+4x^{1}+2x^{1-1}$$

Tango 1 mai i 1.

$$6x^{2}+4x^{1}+2x^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$6x^{2}+4x+2x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$6x^{2}+4x+2\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$6x^{2}+4x+2$$