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Whakaoti mō x
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x^{2}-x+1=0
Kia whakaotia te koreōrite, me tauwehe te taha mauī. Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.
x=\frac{-\left(-1\right)±\sqrt{\left(-1\right)^{2}-4\times 1\times 1}}{2}
Ka taea ngā whārite katoa o te momo ax^{2}+bx+c=0 te whakaoti mā te ture pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Whakakapia te 1 mō te a, te -1 mō te b, me te 1 mō te c i te ture pūrua.
x=\frac{1±\sqrt{-3}}{2}
Mahia ngā tātaitai.
0^{2}-0+1=1
Tā te mea e kore te pūrua o tētahi tau tōraro e tautohutia ki te āpure tūturu, kāhore he rongoā. He rite te tohu o te kīanga x^{2}-x+1 ki tā tētahi x. Kia whakatau i te tohu, tātaitia te uara o te kīanga mō x=0.
x\in \mathrm{R}
Ko te uara o te kīanga x^{2}-x+1 he tōrunga i ngā wā katoa. E mau ana te koreōrite mō x\in \mathrm{R}.