Whakaoti i te x^2-9=9

$${ x }^{ 2 } -9=9$$

Whakaoti mō x

$$x=3\sqrt{2}\approx 4.242640687$$

$$x=-3\sqrt{2}\approx -4.242640687$$

Ngā Upane mā te Kimi Pūtakerua

Me tāpiri te 9 ki ngā taha e rua.

$$x^{2}=9+9$$

Tāpirihia te 9 ki te 9, ka 18.

$$x^{2}=18$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=3\sqrt{2} x=-3\sqrt{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 9 mai i ngā taha e rua.

$$x^{2}-9-9=0$$

Tangohia te 9 i te -9, ka -18.

$$x^{2}-18=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -18 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-18\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-18\right)}}{2}$$

Whakareatia -4 ki te -18.

$$x=\frac{0±\sqrt{72}}{2}$$

Tuhia te pūtakerua o te 72.

$$x=\frac{0±6\sqrt{2}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±6\sqrt{2}}{2} ina he tāpiri te ±.

$$x=3\sqrt{2}$$

Nā, me whakaoti te whārite x=\frac{0±6\sqrt{2}}{2} ina he tango te ±.

$$x=-3\sqrt{2}$$

Kua oti te whārite te whakatau.

$$x=3\sqrt{2} x=-3\sqrt{2}$$