Whakaoti i te x^2-7x+2

$${ x }^{ 2 } -7x+2$$

Tauwehe

$$\left(x-\frac{7-\sqrt{41}}{2}\right)\left(x-\frac{\sqrt{41}+7}{2}\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$x^{2}-7x+2=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-\left(-7\right)±\sqrt{\left(-7\right)^{2}-4\times 2}}{2}$$

Pūrua -7.

$$x=\frac{-\left(-7\right)±\sqrt{49-4\times 2}}{2}$$

Whakareatia -4 ki te 2.

$$x=\frac{-\left(-7\right)±\sqrt{49-8}}{2}$$

Tāpiri 49 ki te -8.

$$x=\frac{-\left(-7\right)±\sqrt{41}}{2}$$

Ko te tauaro o -7 ko 7.

$$x=\frac{7±\sqrt{41}}{2}$$

Nā, me whakaoti te whārite x=\frac{7±\sqrt{41}}{2} ina he tāpiri te ±. Tāpiri 7 ki te \sqrt{41}.

$$x=\frac{\sqrt{41}+7}{2}$$

Nā, me whakaoti te whārite x=\frac{7±\sqrt{41}}{2} ina he tango te ±. Tango \sqrt{41} mai i 7.

$$x=\frac{7-\sqrt{41}}{2}$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te \frac{7+\sqrt{41}}{2} mō te x_{1} me te \frac{7-\sqrt{41}}{2} mō te x_{2}.

$$x^{2}-7x+2=\left(x-\frac{\sqrt{41}+7}{2}\right)\left(x-\frac{7-\sqrt{41}}{2}\right)$$

Aromātai

$$x^{2}-7x+2$$