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x^{2}\leq 5
Me tāpiri te 5 ki ngā taha e rua.
x^{2}\leq \left(\sqrt{5}\right)^{2}
Tātaitia te pūtakerua o 5 kia tae ki \sqrt{5}. Tuhia anō te 5 hei \left(\sqrt{5}\right)^{2}.
|x|\leq \sqrt{5}
E mau ana te koreōrite mō |x|\leq \sqrt{5}.
x\in \begin{bmatrix}-\sqrt{5},\sqrt{5}\end{bmatrix}
Tuhia anō te |x|\leq \sqrt{5} hei x\in \left[-\sqrt{5},\sqrt{5}\right].