Whakaoti i te x^2-2bx-x=0

$${ x }^{ 2 } -2bx-x=0$$

Whakaoti mō b (complex solution)

$$\left\{\begin{matrix}\\b=\frac{x-1}{2}\text{, }&\text{unconditionally}\\b\in \mathrm{C}\text{, }&x=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te x^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-2bx-x=-x^{2}$$

Me tāpiri te x ki ngā taha e rua.

$$-2bx=-x^{2}+x$$

He hanga arowhānui tō te whārite.

$$\left(-2x\right)b=x-x^{2}$$

Whakawehea ngā taha e rua ki te -2x.

$$\frac{\left(-2x\right)b}{-2x}=\frac{x\left(1-x\right)}{-2x}$$

Mā te whakawehe ki te -2x ka wetekia te whakareanga ki te -2x.

$$b=\frac{x\left(1-x\right)}{-2x}$$

Whakawehe x\left(1-x\right) ki te -2x.

$$b=\frac{x-1}{2}$$

Whakaoti mō b

$$\left\{\begin{matrix}\\b=\frac{x-1}{2}\text{, }&\text{unconditionally}\\b\in \mathrm{R}\text{, }&x=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te x^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-2bx-x=-x^{2}$$

Me tāpiri te x ki ngā taha e rua.

$$-2bx=-x^{2}+x$$

He hanga arowhānui tō te whārite.

$$\left(-2x\right)b=x-x^{2}$$

Whakawehea ngā taha e rua ki te -2x.

$$\frac{\left(-2x\right)b}{-2x}=\frac{x\left(1-x\right)}{-2x}$$

Mā te whakawehe ki te -2x ka wetekia te whakareanga ki te -2x.

$$b=\frac{x\left(1-x\right)}{-2x}$$

Whakawehe x\left(1-x\right) ki te -2x.

$$b=\frac{x-1}{2}$$

Whakaoti mō x

$$x=2b+1$$

$$x=0$$