Whakaoti i te x^2-12+32=0

$${ x }^{ 2 } -12+32=0$$

Whakaoti mō x (complex solution)

$$x=-2\sqrt{5}i\approx -0-4.472135955i$$

$$x=2\sqrt{5}i\approx 4.472135955i$$

Ngā Upane mā te Kimi Pūtakerua

Tāpirihia te -12 ki te 32, ka 20.

$$x^{2}+20=0$$

Tangohia te 20 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$x^{2}=-20$$

Kua oti te whārite te whakatau.

$$x=2\sqrt{5}i x=-2\sqrt{5}i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tāpirihia te -12 ki te 32, ka 20.

$$x^{2}+20=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me 20 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 20}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 20}}{2}$$

Whakareatia -4 ki te 20.

$$x=\frac{0±\sqrt{-80}}{2}$$

Tuhia te pūtakerua o te -80.

$$x=\frac{0±4\sqrt{5}i}{2}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{5}i}{2} ina he tāpiri te ±.

$$x=2\sqrt{5}i$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{5}i}{2} ina he tango te ±.

$$x=-2\sqrt{5}i$$

Kua oti te whārite te whakatau.

$$x=2\sqrt{5}i x=-2\sqrt{5}i$$