Whakaoti i te x^2-10+18=0

$${ x }^{ 2 } -10+18=0$$

Whakaoti mō x (complex solution)

$$x=-2\sqrt{2}i\approx -0-2.828427125i$$

$$x=2\sqrt{2}i\approx 2.828427125i$$

Ngā Upane mā te Kimi Pūtakerua

Tāpirihia te -10 ki te 18, ka 8.

$$x^{2}+8=0$$

Tangohia te 8 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$x^{2}=-8$$

Kua oti te whārite te whakatau.

$$x=2\sqrt{2}i x=-2\sqrt{2}i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tāpirihia te -10 ki te 18, ka 8.

$$x^{2}+8=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me 8 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 8}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 8}}{2}$$

Whakareatia -4 ki te 8.

$$x=\frac{0±\sqrt{-32}}{2}$$

Tuhia te pūtakerua o te -32.

$$x=\frac{0±4\sqrt{2}i}{2}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{2}i}{2} ina he tāpiri te ±.

$$x=2\sqrt{2}i$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{2}i}{2} ina he tango te ±.

$$x=-2\sqrt{2}i$$

Kua oti te whārite te whakatau.

$$x=2\sqrt{2}i x=-2\sqrt{2}i$$