Whakaoti i te x^2-frac{sqrt{2}}{2}x+1

$${ x }^{ 2 } - \frac{ \sqrt{ 2 } }{ 2 } x+1$$

Aromātai

$$x^{2}-\frac{\sqrt{2}x}{2}+1$$

Ngā Hipanga Rongoā Poto

Tuhia te \frac{\sqrt{2}}{2}x hei hautanga kotahi.

$$x^{2}-\frac{\sqrt{2}x}{2}+1$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia x^{2} ki te \frac{2}{2}.

$$\frac{2x^{2}}{2}-\frac{\sqrt{2}x}{2}+1$$

Tā te mea he rite te tauraro o \frac{2x^{2}}{2} me \frac{\sqrt{2}x}{2}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{2x^{2}-\sqrt{2}x}{2}+1$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 1 ki te \frac{2}{2}.

$$\frac{2x^{2}-\sqrt{2}x}{2}+\frac{2}{2}$$

Tā te mea he rite te tauraro o \frac{2x^{2}-\sqrt{2}x}{2} me \frac{2}{2}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{2x^{2}-\sqrt{2}x+2}{2}$$

Tauwehe

$$\frac{\sqrt{2}\left(\sqrt{2}x^{2}-x+\sqrt{2}\right)}{2}$$

Ngā Upane Otinga

Tauwehea te \frac{1}{2}.

$$\frac{2x^{2}-\sqrt{2}x+2}{2}$$

Whakaarohia te 2x^{2}-\sqrt{2}x+2. Tauwehea te \sqrt{2}.

$$\sqrt{2}\left(\sqrt{2}x^{2}-x+\sqrt{2}\right)$$

Me tuhi anō te kīanga whakatauwehe katoa. Kāore te pūrau \sqrt{2}x^{2}-x+\sqrt{2} i whakatauwehea i te mea kāhore ōna pūtake whakahau.

$$\frac{\sqrt{2}\left(\sqrt{2}x^{2}-x+\sqrt{2}\right)}{2}$$