Whakaoti i te x^2=e | Kairarau Microsoft

Whakaoti mō x

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Algebra

5 raruraru e ōrite ana ki:

Ngā Raru Ōrite mai i te Rapu Tukutuku

https://math.stackexchange.com/questions/2394655/if-ex2-1-and-ex4-is-finite-then-e-vertx-vert-ge-1-sqrtex4

https://math.stackexchange.com/questions/335846/if-f-g-rightarrow-z-2-is-a-central-extension-of-z-4-by-z-2-then-g-is-is

https://math.stackexchange.com/q/1143405

https://math.stackexchange.com/questions/2805505/if-n-is-a-normal-subgroup-of-g-and-has-an-index-of-12-in-g-then-what-can

https://math.stackexchange.com/questions/549489/prove-of-disprove-for-every-x-in-g-there-exists-some-y-in-g-such-that-x-y

Tohaina

Kua tāruatia ki te papatopenga

x=\sqrt{e} x=-\sqrt{e}

Tuhia te pūtakerua o ngā taha e rua o te whārite.

x^{2}=e

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

x^{2}-e=e-e

Me tango e mai i ngā taha e rua o te whārite.

x^{2}-e=0

Mā te tango i te e i a ia ake anō ka toe ko te 0.

x=\frac{0±\sqrt{0^{2}-4\left(-e\right)}}{2}

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -e mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

x=\frac{0±\sqrt{-4\left(-e\right)}}{2}

Pūrua 0.

x=\frac{0±\sqrt{4e}}{2}

Whakareatia -4 ki te -e.

x=\frac{0±2\sqrt{e}}{2}

Tuhia te pūtakerua o te 4e.