Whakaoti i te x^2=6.25

$${ x }^{ 2 } =6.25$$

Whakaoti mō x

$$x=2.5$$

$$x=-2.5$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tangohia te 6.25 mai i ngā taha e rua.

$$x^{2}-6.25=0$$

Whakaarohia te x^{2}-6.25. Tuhia anō te x^{2}-6.25 hei x^{2}-\left(\frac{5}{2}\right)^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-\frac{5}{2}\right)\left(x+\frac{5}{2}\right)=0$$

Hei kimi otinga whārite, me whakaoti te x-\frac{5}{2}=0 me te x+\frac{5}{2}=0.

$$x=\frac{5}{2} x=-\frac{5}{2}$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{5}{2} x=-\frac{5}{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 6.25 mai i ngā taha e rua.

$$x^{2}-6.25=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -6.25 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-6.25\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-6.25\right)}}{2}$$

Whakareatia -4 ki te -6.25.

$$x=\frac{0±\sqrt{25}}{2}$$

Tuhia te pūtakerua o te 25.

$$x=\frac{0±5}{2}$$

Nā, me whakaoti te whārite x=\frac{0±5}{2} ina he tāpiri te ±. Whakawehe 5 ki te 2.

$$x=\frac{5}{2}$$

Nā, me whakaoti te whārite x=\frac{0±5}{2} ina he tango te ±. Whakawehe -5 ki te 2.

$$x=-\frac{5}{2}$$

Kua oti te whārite te whakatau.

$$x=\frac{5}{2} x=-\frac{5}{2}$$