Whakaoti i te x^2=15

$${ x }^{ 2 } =15$$

Whakaoti mō x

$$x=\sqrt{15}\approx 3.872983346$$

$$x=-\sqrt{15}\approx -3.872983346$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{15} x=-\sqrt{15}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 15 mai i ngā taha e rua.

$$x^{2}-15=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -15 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-15\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-15\right)}}{2}$$

Whakareatia -4 ki te -15.

$$x=\frac{0±\sqrt{60}}{2}$$

Tuhia te pūtakerua o te 60.

$$x=\frac{0±2\sqrt{15}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{15}}{2} ina he tāpiri te ±.

$$x=\sqrt{15}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{15}}{2} ina he tango te ±.

$$x=-\sqrt{15}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{15} x=-\sqrt{15}$$