Whakaoti i te x^2=125

$${ x }^{ 2 } =125$$

Whakaoti mō x

$$x=5\sqrt{5}\approx 11.180339887$$

$$x=-5\sqrt{5}\approx -11.180339887$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=5\sqrt{5} x=-5\sqrt{5}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 125 mai i ngā taha e rua.

$$x^{2}-125=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -125 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-125\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-125\right)}}{2}$$

Whakareatia -4 ki te -125.

$$x=\frac{0±\sqrt{500}}{2}$$

Tuhia te pūtakerua o te 500.

$$x=\frac{0±10\sqrt{5}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±10\sqrt{5}}{2} ina he tāpiri te ±.

$$x=5\sqrt{5}$$

Nā, me whakaoti te whārite x=\frac{0±10\sqrt{5}}{2} ina he tango te ±.

$$x=-5\sqrt{5}$$

Kua oti te whārite te whakatau.

$$x=5\sqrt{5} x=-5\sqrt{5}$$