Whakaoti i te x^2+8x=4y-12

$${ x }^{ 2 } +8x = 4y-12$$

Whakaoti mō y

$$y=\frac{\left(x+2\right)\left(x+6\right)}{4}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$4y-12=x^{2}+8x$$

Me tāpiri te 12 ki ngā taha e rua.

$$4y=x^{2}+8x+12$$

Whakawehea ngā taha e rua ki te 4.

$$\frac{4y}{4}=\frac{\left(x+2\right)\left(x+6\right)}{4}$$

Mā te whakawehe ki te 4 ka wetekia te whakareanga ki te 4.

$$y=\frac{\left(x+2\right)\left(x+6\right)}{4}$$

Whakaoti mō x (complex solution)

$$x=2\sqrt{y+1}-4$$

$$x=-2\sqrt{y+1}-4$$

Whakaoti mō x

$$x=2\sqrt{y+1}-4$$

$$x=-2\sqrt{y+1}-4\text{, }y\geq -1$$