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Whakaoti mō x (complex solution)
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x^{2}+2x+358=29
Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.
x^{2}+2x+358-29=29-29
Me tango 29 mai i ngā taha e rua o te whārite.
x^{2}+2x+358-29=0
Mā te tango i te 29 i a ia ake anō ka toe ko te 0.
x^{2}+2x+329=0
Tango 29 mai i 358.
x=\frac{-2±\sqrt{2^{2}-4\times 329}}{2}
Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 2 mō b, me 329 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-2±\sqrt{4-4\times 329}}{2}
Pūrua 2.
x=\frac{-2±\sqrt{4-1316}}{2}
Whakareatia -4 ki te 329.
x=\frac{-2±\sqrt{-1312}}{2}
Tāpiri 4 ki te -1316.
x=\frac{-2±4\sqrt{82}i}{2}
Tuhia te pūtakerua o te -1312.
x=\frac{-2+4\sqrt{82}i}{2}
Nā, me whakaoti te whārite x=\frac{-2±4\sqrt{82}i}{2} ina he tāpiri te ±. Tāpiri -2 ki te 4i\sqrt{82}.
x=-1+2\sqrt{82}i
Whakawehe -2+4i\sqrt{82} ki te 2.
x=\frac{-4\sqrt{82}i-2}{2}
Nā, me whakaoti te whārite x=\frac{-2±4\sqrt{82}i}{2} ina he tango te ±. Tango 4i\sqrt{82} mai i -2.
x=-2\sqrt{82}i-1
Whakawehe -2-4i\sqrt{82} ki te 2.
x=-1+2\sqrt{82}i x=-2\sqrt{82}i-1
Kua oti te whārite te whakatau.
x^{2}+2x+358=29
Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.
x^{2}+2x+358-358=29-358
Me tango 358 mai i ngā taha e rua o te whārite.
x^{2}+2x=29-358
Mā te tango i te 358 i a ia ake anō ka toe ko te 0.
x^{2}+2x=-329
Tango 358 mai i 29.
x^{2}+2x+1^{2}=-329+1^{2}
Whakawehea te 2, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te 1. Nā, tāpiria te pūrua o te 1 ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.
x^{2}+2x+1=-329+1
Pūrua 1.
x^{2}+2x+1=-328
Tāpiri -329 ki te 1.
\left(x+1\right)^{2}=-328
Tauwehea x^{2}+2x+1. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+1\right)^{2}}=\sqrt{-328}
Tuhia te pūtakerua o ngā taha e rua o te whārite.
x+1=2\sqrt{82}i x+1=-2\sqrt{82}i
Whakarūnātia.
x=-1+2\sqrt{82}i x=-2\sqrt{82}i-1
Me tango 1 mai i ngā taha e rua o te whārite.