Whakaoti i te x^2+28=78

$${ x }^{ 2 } +28=78$$

Whakaoti mō x

$$x=5\sqrt{2}\approx 7.071067812$$

$$x=-5\sqrt{2}\approx -7.071067812$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 28 mai i ngā taha e rua.

$$x^{2}=78-28$$

Tangohia te 28 i te 78, ka 50.

$$x^{2}=50$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=5\sqrt{2} x=-5\sqrt{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 78 mai i ngā taha e rua.

$$x^{2}+28-78=0$$

Tangohia te 78 i te 28, ka -50.

$$x^{2}-50=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -50 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-50\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-50\right)}}{2}$$

Whakareatia -4 ki te -50.

$$x=\frac{0±\sqrt{200}}{2}$$

Tuhia te pūtakerua o te 200.

$$x=\frac{0±10\sqrt{2}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±10\sqrt{2}}{2} ina he tāpiri te ±.

$$x=5\sqrt{2}$$

Nā, me whakaoti te whārite x=\frac{0±10\sqrt{2}}{2} ina he tango te ±.

$$x=-5\sqrt{2}$$

Kua oti te whārite te whakatau.

$$x=5\sqrt{2} x=-5\sqrt{2}$$