Whakaoti i te x^2+25=64

$${ x }^{ 2 } +25=64$$

Whakaoti mō x

$$x=\sqrt{39}\approx 6.244997998$$

$$x=-\sqrt{39}\approx -6.244997998$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 25 mai i ngā taha e rua.

$$x^{2}=64-25$$

Tangohia te 25 i te 64, ka 39.

$$x^{2}=39$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{39} x=-\sqrt{39}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 64 mai i ngā taha e rua.

$$x^{2}+25-64=0$$

Tangohia te 64 i te 25, ka -39.

$$x^{2}-39=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -39 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-39\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-39\right)}}{2}$$

Whakareatia -4 ki te -39.

$$x=\frac{0±\sqrt{156}}{2}$$

Tuhia te pūtakerua o te 156.

$$x=\frac{0±2\sqrt{39}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{39}}{2} ina he tāpiri te ±.

$$x=\sqrt{39}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{39}}{2} ina he tango te ±.

$$x=-\sqrt{39}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{39} x=-\sqrt{39}$$