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x^{2}+20x+17=-3
Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.
x^{2}+20x+17-\left(-3\right)=-3-\left(-3\right)
Me tāpiri 3 ki ngā taha e rua o te whārite.
x^{2}+20x+17-\left(-3\right)=0
Mā te tango i te -3 i a ia ake anō ka toe ko te 0.
x^{2}+20x+20=0
Tango -3 mai i 17.
x=\frac{-20±\sqrt{20^{2}-4\times 20}}{2}
Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 20 mō b, me 20 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-20±\sqrt{400-4\times 20}}{2}
Pūrua 20.
x=\frac{-20±\sqrt{400-80}}{2}
Whakareatia -4 ki te 20.
x=\frac{-20±\sqrt{320}}{2}
Tāpiri 400 ki te -80.
x=\frac{-20±8\sqrt{5}}{2}
Tuhia te pūtakerua o te 320.
x=\frac{8\sqrt{5}-20}{2}
Nā, me whakaoti te whārite x=\frac{-20±8\sqrt{5}}{2} ina he tāpiri te ±. Tāpiri -20 ki te 8\sqrt{5}.
x=4\sqrt{5}-10
Whakawehe -20+8\sqrt{5} ki te 2.
x=\frac{-8\sqrt{5}-20}{2}
Nā, me whakaoti te whārite x=\frac{-20±8\sqrt{5}}{2} ina he tango te ±. Tango 8\sqrt{5} mai i -20.
x=-4\sqrt{5}-10
Whakawehe -20-8\sqrt{5} ki te 2.
x=4\sqrt{5}-10 x=-4\sqrt{5}-10
Kua oti te whārite te whakatau.
x^{2}+20x+17=-3
Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.
x^{2}+20x+17-17=-3-17
Me tango 17 mai i ngā taha e rua o te whārite.
x^{2}+20x=-3-17
Mā te tango i te 17 i a ia ake anō ka toe ko te 0.
x^{2}+20x=-20
Tango 17 mai i -3.
x^{2}+20x+10^{2}=-20+10^{2}
Whakawehea te 20, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te 10. Nā, tāpiria te pūrua o te 10 ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.
x^{2}+20x+100=-20+100
Pūrua 10.
x^{2}+20x+100=80
Tāpiri -20 ki te 100.
\left(x+10\right)^{2}=80
Tauwehea x^{2}+20x+100. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+10\right)^{2}}=\sqrt{80}
Tuhia te pūtakerua o ngā taha e rua o te whārite.
x+10=4\sqrt{5} x+10=-4\sqrt{5}
Whakarūnātia.
x=4\sqrt{5}-10 x=-4\sqrt{5}-10
Me tango 10 mai i ngā taha e rua o te whārite.