Whakaoti i te x^2+x^2=9/6

$${ x }^{ 2 } + { x }^{ 2 } = \frac{ 9 }{ 6 }$$

Whakaoti mō x

$$x=\frac{\sqrt{3}}{2}\approx 0.866025404$$

$$x=-\frac{\sqrt{3}}{2}\approx -0.866025404$$

Ngā Upane mā te Kimi Pūtakerua

Pahekotia te x^{2} me x^{2}, ka 2x^{2}.

$$2x^{2}=\frac{9}{6}$$

Whakahekea te hautanga \frac{9}{6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$2x^{2}=\frac{3}{2}$$

Whakawehea ngā taha e rua ki te 2.

$$x^{2}=\frac{\frac{3}{2}}{2}$$

Tuhia te \frac{\frac{3}{2}}{2} hei hautanga kotahi.

$$x^{2}=\frac{3}{2\times 2}$$

Whakareatia te 2 ki te 2, ka 4.

$$x^{2}=\frac{3}{4}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{\sqrt{3}}{2} x=-\frac{\sqrt{3}}{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Pahekotia te x^{2} me x^{2}, ka 2x^{2}.

$$2x^{2}=\frac{9}{6}$$

Whakahekea te hautanga \frac{9}{6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$2x^{2}=\frac{3}{2}$$

Tangohia te \frac{3}{2} mai i ngā taha e rua.

$$2x^{2}-\frac{3}{2}=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 2 mō a, 0 mō b, me -\frac{3}{2} mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 2\left(-\frac{3}{2}\right)}}{2\times 2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 2\left(-\frac{3}{2}\right)}}{2\times 2}$$

Whakareatia -4 ki te 2.

$$x=\frac{0±\sqrt{-8\left(-\frac{3}{2}\right)}}{2\times 2}$$

Whakareatia -8 ki te -\frac{3}{2}.

$$x=\frac{0±\sqrt{12}}{2\times 2}$$

Tuhia te pūtakerua o te 12.

$$x=\frac{0±2\sqrt{3}}{2\times 2}$$

Whakareatia 2 ki te 2.

$$x=\frac{0±2\sqrt{3}}{4}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{3}}{4} ina he tāpiri te ±.

$$x=\frac{\sqrt{3}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{3}}{4} ina he tango te ±.

$$x=-\frac{\sqrt{3}}{2}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{3}}{2} x=-\frac{\sqrt{3}}{2}$$