Whakaoti i te x^2=1/2-2

$${ x }^{ 2 } = \frac{ 1 }{ 2 } -2$$

Whakaoti mō x (complex solution)

$$x=-\frac{\sqrt{6}i}{2}\approx -0-1.224744871i$$

$$x=\frac{\sqrt{6}i}{2}\approx 1.224744871i$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 2 i te \frac{1}{2}, ka -\frac{3}{2}.

$$x^{2}=-\frac{3}{2}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{6}i}{2} x=-\frac{\sqrt{6}i}{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 2 i te \frac{1}{2}, ka -\frac{3}{2}.

$$x^{2}=-\frac{3}{2}$$

Me tāpiri te \frac{3}{2} ki ngā taha e rua.

$$x^{2}+\frac{3}{2}=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me \frac{3}{2} mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times \frac{3}{2}}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times \frac{3}{2}}}{2}$$

Whakareatia -4 ki te \frac{3}{2}.

$$x=\frac{0±\sqrt{-6}}{2}$$

Tuhia te pūtakerua o te -6.

$$x=\frac{0±\sqrt{6}i}{2}$$

Nā, me whakaoti te whārite x=\frac{0±\sqrt{6}i}{2} ina he tāpiri te ±.

$$x=\frac{\sqrt{6}i}{2}$$

Nā, me whakaoti te whārite x=\frac{0±\sqrt{6}i}{2} ina he tango te ±.

$$x=-\frac{\sqrt{6}i}{2}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{6}i}{2} x=-\frac{\sqrt{6}i}{2}$$