Whakaoti i te x^2=1/2

$${ x }^{ 2 } = \frac{ 1 }{ 2 }$$

Whakaoti mō x

$$x=\frac{\sqrt{2}}{2}\approx 0.707106781$$

$$x=-\frac{\sqrt{2}}{2}\approx -0.707106781$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{\sqrt{2}}{2} x=-\frac{\sqrt{2}}{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te \frac{1}{2} mai i ngā taha e rua.

$$x^{2}-\frac{1}{2}=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -\frac{1}{2} mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-\frac{1}{2}\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-\frac{1}{2}\right)}}{2}$$

Whakareatia -4 ki te -\frac{1}{2}.

$$x=\frac{0±\sqrt{2}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±\sqrt{2}}{2} ina he tāpiri te ±.

$$x=\frac{\sqrt{2}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±\sqrt{2}}{2} ina he tango te ±.

$$x=-\frac{\sqrt{2}}{2}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{2}}{2} x=-\frac{\sqrt{2}}{2}$$