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Whakaoti mō b (complex solution)
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Whakaoti mō b
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Tohaina

t^{2}-29t-96=0
Whakakapia te t mō te b^{2}.
t=\frac{-\left(-29\right)±\sqrt{\left(-29\right)^{2}-4\times 1\left(-96\right)}}{2}
Ka taea ngā whārite katoa o te momo ax^{2}+bx+c=0 te whakaoti mā te ture pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Whakakapia te 1 mō te a, te -29 mō te b, me te -96 mō te c i te ture pūrua.
t=\frac{29±35}{2}
Mahia ngā tātaitai.
t=32 t=-3
Whakaotia te whārite t=\frac{29±35}{2} ina he tōrunga te ±, ina he tōraro te ±.
b=-4\sqrt{2} b=4\sqrt{2} b=-\sqrt{3}i b=\sqrt{3}i
I te mea ko b=t^{2}, ka riro ngā otinga mā te arotake i te b=±\sqrt{t} mō ia t.
t^{2}-29t-96=0
Whakakapia te t mō te b^{2}.
t=\frac{-\left(-29\right)±\sqrt{\left(-29\right)^{2}-4\times 1\left(-96\right)}}{2}
Ka taea ngā whārite katoa o te momo ax^{2}+bx+c=0 te whakaoti mā te ture pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Whakakapia te 1 mō te a, te -29 mō te b, me te -96 mō te c i te ture pūrua.
t=\frac{29±35}{2}
Mahia ngā tātaitai.
t=32 t=-3
Whakaotia te whārite t=\frac{29±35}{2} ina he tōrunga te ±, ina he tōraro te ±.
b=4\sqrt{2} b=-4\sqrt{2}
I te mea ko b=t^{2}, ka riro ngā otinga mā te arotake i te b=±\sqrt{t} mō t tōrunga.