Whakaoti i te 6^2=x(x*3)

$${ 6 }^{ 2 } =x(x \times 3)$$

Whakaoti mō x

$$x=2\sqrt{3}\approx 3.464101615$$

$$x=-2\sqrt{3}\approx -3.464101615$$

Ngā Upane mā te Kimi Pūtakerua

Whakareatia te x ki te x, ka x^{2}.

$$6^{2}=x^{2}\times 3$$

Tātaihia te 6 mā te pū o 2, kia riro ko 36.

$$36=x^{2}\times 3$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$x^{2}\times 3=36$$

Whakawehea ngā taha e rua ki te 3.

$$x^{2}=\frac{36}{3}$$

Whakawehea te 36 ki te 3, kia riro ko 12.

$$x^{2}=12$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=2\sqrt{3} x=-2\sqrt{3}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakareatia te x ki te x, ka x^{2}.

$$6^{2}=x^{2}\times 3$$

Tātaihia te 6 mā te pū o 2, kia riro ko 36.

$$36=x^{2}\times 3$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$x^{2}\times 3=36$$

Tangohia te 36 mai i ngā taha e rua.

$$x^{2}\times 3-36=0$$

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$3x^{2}-36=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 3 mō a, 0 mō b, me -36 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 3\left(-36\right)}}{2\times 3}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 3\left(-36\right)}}{2\times 3}$$

Whakareatia -4 ki te 3.

$$x=\frac{0±\sqrt{-12\left(-36\right)}}{2\times 3}$$

Whakareatia -12 ki te -36.

$$x=\frac{0±\sqrt{432}}{2\times 3}$$

Tuhia te pūtakerua o te 432.

$$x=\frac{0±12\sqrt{3}}{2\times 3}$$

Whakareatia 2 ki te 3.

$$x=\frac{0±12\sqrt{3}}{6}$$

Nā, me whakaoti te whārite x=\frac{0±12\sqrt{3}}{6} ina he tāpiri te ±.

$$x=2\sqrt{3}$$

Nā, me whakaoti te whārite x=\frac{0±12\sqrt{3}}{6} ina he tango te ±.

$$x=-2\sqrt{3}$$

Kua oti te whārite te whakatau.

$$x=2\sqrt{3} x=-2\sqrt{3}$$