Whakaoti i te 3^x+118/3=19

$${ 3 }^{ x+1 } \frac{ 18 }{ 3 } =19$$

Whakaoti mō x

$$x=-\log_{3}\left(\frac{2}{19}\right)-2\approx 0.049214106$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Taupū Kōaro

Whakamahia ngā ture taupū me ngā taupū kōaro hei whakaoti i te whārite.

$$6\times 3^{x+1}=19$$

Whakawehea ngā taha e rua ki te 6.

$$3^{x+1}=\frac{19}{6}$$

Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.

$$\log(3^{x+1})=\log(\frac{19}{6})$$

Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.

$$\left(x+1\right)\log(3)=\log(\frac{19}{6})$$

Whakawehea ngā taha e rua ki te \log(3).

$$x+1=\frac{\log(\frac{19}{6})}{\log(3)}$$

Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x+1=\log_{3}\left(\frac{19}{6}\right)$$

Me tango 1 mai i ngā taha e rua o te whārite.

$$x=\frac{\ln(\frac{19}{6})}{\ln(3)}-1$$