Whakaoti i te left(x+5right)^2=-20(y-95)

$${ \left(x+5 \right) }^{ 2 } =-20(y-95)$$

Whakaoti mō y

$$y=-\frac{\left(x+5\right)^{2}}{20}+95$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+5\right)^{2}.

$$x^{2}+10x+25=-20\left(y-95\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -20 ki te y-95.

$$x^{2}+10x+25=-20y+1900$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-20y+1900=x^{2}+10x+25$$

Tangohia te 1900 mai i ngā taha e rua.

$$-20y=x^{2}+10x+25-1900$$

Tangohia te 1900 i te 25, ka -1875.

$$-20y=x^{2}+10x-1875$$

Whakawehea ngā taha e rua ki te -20.

$$\frac{-20y}{-20}=\frac{x^{2}+10x-1875}{-20}$$

Mā te whakawehe ki te -20 ka wetekia te whakareanga ki te -20.

$$y=\frac{x^{2}+10x-1875}{-20}$$

Whakawehe x^{2}+10x-1875 ki te -20.

$$y=-\frac{x^{2}}{20}-\frac{x}{2}+\frac{375}{4}$$

Whakaoti mō x (complex solution)

$$x=-2\sqrt{475-5y}-5$$

$$x=2\sqrt{475-5y}-5$$

Whakaoti mō x

$$x=-2\sqrt{475-5y}-5$$

$$x=2\sqrt{475-5y}-5\text{, }y\leq 95$$