Whakaoti i te left(x+1right)^2=16

$${ \left(x+1 \right) }^{ 2 } = 16$$

Whakaoti mō x

$$x=3$$

$$x=-5$$

Ngā Upane Whakamahi Tauwehe

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+1\right)^{2}.

$$x^{2}+2x+1=16$$

Tangohia te 16 mai i ngā taha e rua.

$$x^{2}+2x+1-16=0$$

Tangohia te 16 i te 1, ka -15.

$$x^{2}+2x-15=0$$

Hei whakaoti i te whārite, whakatauwehea te x^{2}+2x-15 mā te whakamahi i te tātai x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=2 ab=-15$$

I te mea kua tōraro te ab, he tauaro ngā tohu o a me b. I te mea kua tōrunga te a+b, he nui ake te uara pū o te tau tōrunga i tō te tōraro. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua -15.

$$-1,15 -3,5$$

Tātaihia te tapeke mō ia takirua.

$$-1+15=14 -3+5=2$$

Ko te otinga te takirua ka hoatu i te tapeke 2.

$$a=-3 b=5$$

Me tuhi anō te kīanga whakatauwehe \left(x+a\right)\left(x+b\right) mā ngā uara i tātaihia.

$$\left(x-3\right)\left(x+5\right)$$

Hei kimi otinga whārite, me whakaoti te x-3=0 me te x+5=0.

$$x=3 x=-5$$

Ngā Upane Whakamahi Tauwehe Mā te Whakarōpū

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+1\right)^{2}.

$$x^{2}+2x+1=16$$

Tangohia te 16 mai i ngā taha e rua.

$$x^{2}+2x+1-16=0$$

Tangohia te 16 i te 1, ka -15.

$$x^{2}+2x-15=0$$

Hei whakaoti i te whārite, whakatauwehea te taha mauī mā te whakarōpū. Tuatahi, me tuhi anō te taha mauī hei x^{2}+ax+bx-15. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=2 ab=1\left(-15\right)=-15$$

I te mea kua tōraro te ab, he tauaro ngā tohu o a me b. I te mea kua tōrunga te a+b, he nui ake te uara pū o te tau tōrunga i tō te tōraro. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua -15.

$$-1,15 -3,5$$

Tātaihia te tapeke mō ia takirua.

$$-1+15=14 -3+5=2$$

Ko te otinga te takirua ka hoatu i te tapeke 2.

$$a=-3 b=5$$

Tuhia anō te x^{2}+2x-15 hei \left(x^{2}-3x\right)+\left(5x-15\right).

$$\left(x^{2}-3x\right)+\left(5x-15\right)$$

Tauwehea te x i te tuatahi me te 5 i te rōpū tuarua.

$$x\left(x-3\right)+5\left(x-3\right)$$

Whakatauwehea atu te kīanga pātahi x-3 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(x-3\right)\left(x+5\right)$$

Hei kimi otinga whārite, me whakaoti te x-3=0 me te x+5=0.

$$x=3 x=-5$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+1\right)^{2}.

$$x^{2}+2x+1=16$$

Tangohia te 16 mai i ngā taha e rua.

$$x^{2}+2x+1-16=0$$

Tangohia te 16 i te 1, ka -15.

$$x^{2}+2x-15=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 2 mō b, me -15 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-2±\sqrt{2^{2}-4\left(-15\right)}}{2}$$

Pūrua 2.

$$x=\frac{-2±\sqrt{4-4\left(-15\right)}}{2}$$

Whakareatia -4 ki te -15.

$$x=\frac{-2±\sqrt{4+60}}{2}$$

Tāpiri 4 ki te 60.

$$x=\frac{-2±\sqrt{64}}{2}$$

Tuhia te pūtakerua o te 64.

$$x=\frac{-2±8}{2}$$

Nā, me whakaoti te whārite x=\frac{-2±8}{2} ina he tāpiri te ±. Tāpiri -2 ki te 8.

$$x=\frac{6}{2}$$

Whakawehe 6 ki te 2.

$$x=3$$

Nā, me whakaoti te whārite x=\frac{-2±8}{2} ina he tango te ±. Tango 8 mai i -2.

$$x=-\frac{10}{2}$$

Whakawehe -10 ki te 2.

$$x=-5$$

Kua oti te whārite te whakatau.

$$x=3 x=-5$$

Ngā Upane mō te Whakaoti i te Pūrua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x+1\right)^{2}}=\sqrt{16}$$

Whakarūnātia.

$$x+1=4 x+1=-4$$

Me tango 1 mai i ngā taha e rua o te whārite.

$$x=3 x=-5$$