Whakaoti i te left(6x+2right)^2-10=0

$${ \left(6x+2 \right) }^{ 2 } -10=0$$

Whakaoti mō x

$$x=\frac{\sqrt{10}}{6}-\frac{1}{3}\approx 0.193712943$$

$$x=-\frac{\sqrt{10}}{6}-\frac{1}{3}\approx -0.86037961$$

Ngā Upane mā te Kimi Pūtakerua

Me tāpiri 10 ki ngā taha e rua o te whārite.

$$\left(6x+2\right)^{2}-10+10=10$$

Mā te tango i te 10 i a ia ake anō ka toe ko te 0.

$$\left(6x+2\right)^{2}=10$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$6x+2=\sqrt{10} 6x+2=-\sqrt{10}$$

Me tango 2 mai i ngā taha e rua o te whārite.

$$6x+2-2=\sqrt{10}-2 6x+2-2=-\sqrt{10}-2$$

Mā te tango i te 2 i a ia ake anō ka toe ko te 0.

$$6x=\sqrt{10}-2 6x=-\sqrt{10}-2$$

Tango 2 mai i \sqrt{10}.

$$6x=\sqrt{10}-2$$

Tango 2 mai i -\sqrt{10}.

$$6x=-\sqrt{10}-2$$

Whakawehea ngā taha e rua ki te 6.

$$\frac{6x}{6}=\frac{\sqrt{10}-2}{6} \frac{6x}{6}=\frac{-\sqrt{10}-2}{6}$$

Mā te whakawehe ki te 6 ka wetekia te whakareanga ki te 6.

$$x=\frac{\sqrt{10}-2}{6} x=\frac{-\sqrt{10}-2}{6}$$

Whakawehe \sqrt{10}-2 ki te 6.

$$x=\frac{\sqrt{10}}{6}-\frac{1}{3}$$

Whakawehe -\sqrt{10}-2 ki te 6.

$$x=-\frac{\sqrt{10}}{6}-\frac{1}{3}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{10}}{6}-\frac{1}{3} x=-\frac{\sqrt{10}}{6}-\frac{1}{3}$$