Whakaoti i te left(4-xright)^2=x^2+9

$${ \left(4-x \right) }^{ 2 } = { x }^{ 2 } +9$$

Whakaoti mō x

$$x=\frac{7}{8}=0.875$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(4-x\right)^{2}.

$$16-8x+x^{2}=x^{2}+9$$

Tangohia te x^{2} mai i ngā taha e rua.

$$16-8x+x^{2}-x^{2}=9$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$16-8x=9$$

Tangohia te 16 mai i ngā taha e rua.

$$-8x=9-16$$

Tangohia te 16 i te 9, ka -7.

$$-8x=-7$$

Whakawehea ngā taha e rua ki te -8.

$$x=\frac{-7}{-8}$$

Ka taea te hautanga \frac{-7}{-8} te whakamāmā ki te \frac{7}{8} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x=\frac{7}{8}$$