Whakaoti i te left(2xright)^1+2-2^2+2

$${ \left(2x \right) }^{ 1+2 } - { 2 }^{ 2+2 }$$

Aromātai

$$8\left(x^{3}-2\right)$$

Ngā Upane Otinga

Tāpirihia te 1 ki te 2, ka 3.

$$\left(2x\right)^{3}-2^{2+2}$$

Whakarohaina te \left(2x\right)^{3}.

$$2^{3}x^{3}-2^{2+2}$$

Tātaihia te 2 mā te pū o 3, kia riro ko 8.

$$8x^{3}-2^{2+2}$$

Tāpirihia te 2 ki te 2, ka 4.

$$8x^{3}-2^{4}$$

Tātaihia te 2 mā te pū o 4, kia riro ko 16.

$$8x^{3}-16$$

Kimi Pārōnaki e ai ki x

$$24x^{2}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Tāpirihia te 1 ki te 2, ka 3.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\left(2x\right)^{3}-2^{2+2})$$

Whakarohaina te \left(2x\right)^{3}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2^{3}x^{3}-2^{2+2})$$

Tātaihia te 2 mā te pū o 3, kia riro ko 8.

$$\frac{\mathrm{d}}{\mathrm{d}x}(8x^{3}-2^{2+2})$$

Tāpirihia te 2 ki te 2, ka 4.

$$\frac{\mathrm{d}}{\mathrm{d}x}(8x^{3}-2^{4})$$

Tātaihia te 2 mā te pū o 4, kia riro ko 16.

$$\frac{\mathrm{d}}{\mathrm{d}x}(8x^{3}-16)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3\times 8x^{3-1}$$

Whakareatia 3 ki te 8.

$$24x^{3-1}$$

Tango 1 mai i 3.

$$24x^{2}$$