Whakaoti i te left(x^-3right)^2

$${ \left( { x }^{ -3 } \right) }^{ 2 }$$

Aromātai

$$\frac{1}{x^{6}}$$

Ngā Upane mō te Hāpai i Tētahi Pū ki Tētahi Atu Pū

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\left(x^{-3}\right)^{2}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū.

$$x^{-3\times 2}$$

Whakareatia -3 ki te 2.

$$\frac{1}{x^{6}}$$

Kimi Pārōnaki e ai ki x

$$-\frac{6}{x^{7}}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$2\left(x^{-3}\right)^{2-1}\frac{\mathrm{d}}{\mathrm{d}x}(x^{-3})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$2\left(x^{-3}\right)^{1}\left(-3\right)x^{-3-1}$$

Whakarūnātia.

$$-6x^{-4}\left(x^{-3}\right)^{1}$$

Mō tētahi kupu t, t^{1}=t.

$$-6x^{-4}x^{-3}$$