Whakaoti i te left(x^-2right)^10

$${ \left( { x }^{ -2 } \right) }^{ 10 }$$

Aromātai

$$\frac{1}{x^{20}}$$

Ngā Upane mō te Hāpai i Tētahi Pū ki Tētahi Atu Pū

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\left(x^{-2}\right)^{10}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū.

$$x^{-2\times 10}$$

Whakareatia -2 ki te 10.

$$\frac{1}{x^{20}}$$

Kimi Pārōnaki e ai ki x

$$-\frac{20}{x^{21}}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$10\left(x^{-2}\right)^{10-1}\frac{\mathrm{d}}{\mathrm{d}x}(x^{-2})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$10\left(x^{-2}\right)^{9}\left(-2\right)x^{-2-1}$$

Whakarūnātia.

$$-20x^{-3}\left(x^{-2}\right)^{9}$$