Whakaoti i te {left(sqrt{x^4}right)}^2*{left(sqrt{x^8}right)}^2*{left(sqrt{x^2}right)}^2

$${ \left( \sqrt{ { x }^{ 4 } } \right) }^{ 2 } \times { \left( \sqrt{ { x }^{ 8 } } \right) }^{ 2 } \times { \left( \sqrt{ { x }^{ 2 } } \right) }^{ 2 }$$

Aromātai

$$x^{14}$$

Ngā Upane Otinga

Tātaihia te \sqrt{x^{4}} mā te pū o 2, kia riro ko x^{4}.

$$x^{4}\left(\sqrt{x^{8}}\right)^{2}\left(\sqrt{x^{2}}\right)^{2}$$

Tātaihia te \sqrt{x^{8}} mā te pū o 2, kia riro ko x^{8}.

$$x^{4}x^{8}\left(\sqrt{x^{2}}\right)^{2}$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 4 me te 8 kia riro ai te 12.

$$x^{12}\left(\sqrt{x^{2}}\right)^{2}$$

Tātaihia te \sqrt{x^{2}} mā te pū o 2, kia riro ko x^{2}.

$$x^{12}x^{2}$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 12 me te 2 kia riro ai te 14.

$$x^{14}$$

Kimi Pārōnaki e ai ki x

$$14x^{13}$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Pārōnaki

Tātaihia te \sqrt{x^{4}} mā te pū o 2, kia riro ko x^{4}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{4}\left(\sqrt{x^{8}}\right)^{2}\left(\sqrt{x^{2}}\right)^{2})$$

Tātaihia te \sqrt{x^{8}} mā te pū o 2, kia riro ko x^{8}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{4}x^{8}\left(\sqrt{x^{2}}\right)^{2})$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 4 me te 8 kia riro ai te 12.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{12}\left(\sqrt{x^{2}}\right)^{2})$$

Tātaihia te \sqrt{x^{2}} mā te pū o 2, kia riro ko x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{12}x^{2})$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 12 me te 2 kia riro ai te 14.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{14})$$

Ko te pārōnaki o ax^{n} ko nax^{n-1}.

$$14x^{14-1}$$

Tango 1 mai i 14.

$$14x^{13}$$