Whakaoti i te left(sec(x)right)^2-left(tan(x)right)^2

$${ \left( \sec ( x ) \right) }^{ 2 } - { \left( \tan ( x ) \right) }^{ 2 }$$

Tauwehe

$$1$$

Ngā Upane Otinga

Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(\frac{1}{\cos(x)}-\tan(x)\right)\left(\frac{1}{\cos(x)}+\tan(x)\right)$$

Whakaarohia te \frac{1}{\cos(x)}-\tan(x). Tauwehea te \frac{1}{\cos(x)}.

$$\frac{1-\sin(x)}{\cos(x)}$$

Whakaarohia te \frac{1}{\cos(x)}+\tan(x). Tauwehea te \frac{1}{\cos(x)}.

$$\frac{1+\sin(x)}{\cos(x)}$$

Me tuhi anō te kīanga whakatauwehe katoa.

$$\left(1-\sin(x)\right)\left(1+\sin(x)\right)\times \left(\frac{1}{\cos(x)}\right)^{2}$$

Aromātai

$$1$$