Whakaoti i te {left(16+8x+2x^2/2+xright)}^2-4

$${ \left( \frac{ 16+8x+2 { x }^{ 2 } }{ 2+x } \right) }^{ 2 } -4$$

Aromātai

$$\frac{4\left(x^{2}+3x+6\right)\left(x^{2}+5x+10\right)}{\left(x+2\right)^{2}}$$

Ngā Hipanga Rongoā Poto

Kia whakarewa i te \frac{16+8x+2x^{2}}{2+x} ki tētahi taupū, me whakarewa tahi te taurunga me te tauraro ki te taupū kātahi ka whakawehe.

$$\frac{\left(16+8x+2x^{2}\right)^{2}}{\left(2+x\right)^{2}}-4$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 4 ki te \frac{\left(2+x\right)^{2}}{\left(2+x\right)^{2}}.

$$\frac{\left(16+8x+2x^{2}\right)^{2}}{\left(2+x\right)^{2}}-\frac{4\left(2+x\right)^{2}}{\left(2+x\right)^{2}}$$

Tā te mea he rite te tauraro o \frac{\left(16+8x+2x^{2}\right)^{2}}{\left(2+x\right)^{2}} me \frac{4\left(2+x\right)^{2}}{\left(2+x\right)^{2}}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{\left(16+8x+2x^{2}\right)^{2}-4\left(2+x\right)^{2}}{\left(2+x\right)^{2}}$$

Mahia ngā whakarea i roto o \left(16+8x+2x^{2}\right)^{2}-4\left(2+x\right)^{2}.

$$\frac{256+128x+32x^{2}+128x+64x^{2}+16x^{3}+32x^{2}+16x^{3}+4x^{4}-16-16x-4x^{2}}{\left(2+x\right)^{2}}$$

Whakakotahitia ngā kupu rite i 256+128x+32x^{2}+128x+64x^{2}+16x^{3}+32x^{2}+16x^{3}+4x^{4}-16-16x-4x^{2}.

$$\frac{240+240x+124x^{2}+32x^{3}+4x^{4}}{\left(2+x\right)^{2}}$$

Whakarohaina te \left(2+x\right)^{2}.

$$\frac{240+240x+124x^{2}+32x^{3}+4x^{4}}{x^{2}+4x+4}$$

Whakaroha

$$\frac{4\left(x^{4}+8x^{3}+31x^{2}+60x+60\right)}{\left(x+2\right)^{2}}$$

Ngā Hipanga Rongoā Poto

Kia whakarewa i te \frac{16+8x+2x^{2}}{2+x} ki tētahi taupū, me whakarewa tahi te taurunga me te tauraro ki te taupū kātahi ka whakawehe.

$$\frac{\left(16+8x+2x^{2}\right)^{2}}{\left(2+x\right)^{2}}-4$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 4 ki te \frac{\left(2+x\right)^{2}}{\left(2+x\right)^{2}}.

$$\frac{\left(16+8x+2x^{2}\right)^{2}}{\left(2+x\right)^{2}}-\frac{4\left(2+x\right)^{2}}{\left(2+x\right)^{2}}$$

Tā te mea he rite te tauraro o \frac{\left(16+8x+2x^{2}\right)^{2}}{\left(2+x\right)^{2}} me \frac{4\left(2+x\right)^{2}}{\left(2+x\right)^{2}}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{\left(16+8x+2x^{2}\right)^{2}-4\left(2+x\right)^{2}}{\left(2+x\right)^{2}}$$

Mahia ngā whakarea i roto o \left(16+8x+2x^{2}\right)^{2}-4\left(2+x\right)^{2}.

$$\frac{256+128x+32x^{2}+128x+64x^{2}+16x^{3}+32x^{2}+16x^{3}+4x^{4}-16-16x-4x^{2}}{\left(2+x\right)^{2}}$$

Whakakotahitia ngā kupu rite i 256+128x+32x^{2}+128x+64x^{2}+16x^{3}+32x^{2}+16x^{3}+4x^{4}-16-16x-4x^{2}.

$$\frac{240+240x+124x^{2}+32x^{3}+4x^{4}}{\left(2+x\right)^{2}}$$

Whakarohaina te \left(2+x\right)^{2}.

$$\frac{240+240x+124x^{2}+32x^{3}+4x^{4}}{x^{2}+4x+4}$$