Whakaoti i te θ=6/11+f(sin140^circ)

$$\theta = 6 / 11 + f ( \sin 140 ^ { \circ } )$$

Whakaoti mō f_0

$$f_{0}=\frac{2000000000000000\theta }{1285575219373079}-\frac{12000000000000000}{14141327413103869}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Evaluate trigonometric functions in the problem

$$\theta = \frac{6}{11} + f 0.6427876096865395$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\frac{6}{11}+f_{0}\times 0.6427876096865395=\theta$$

Tangohia te \frac{6}{11} mai i ngā taha e rua.

$$f_{0}\times 0.6427876096865395=\theta -\frac{6}{11}$$

He hanga arowhānui tō te whārite.

$$0.6427876096865395f_{0}=\theta -\frac{6}{11}$$

Whakawehea ngā taha e rua o te whārite ki te 0.6427876096865395, he ōrite ki te whakarea i ngā taha e rua ki te tau huripoki o te hautanga.

$$\frac{0.6427876096865395f_{0}}{0.6427876096865395}=\frac{\theta -\frac{6}{11}}{0.6427876096865395}$$

Mā te whakawehe ki te 0.6427876096865395 ka wetekia te whakareanga ki te 0.6427876096865395.

$$f_{0}=\frac{\theta -\frac{6}{11}}{0.6427876096865395}$$

Whakawehe \theta -\frac{6}{11} ki te 0.6427876096865395 mā te whakarea \theta -\frac{6}{11} ki te tau huripoki o 0.6427876096865395.

$$f_{0}=\frac{2000000000000000\theta }{1285575219373079}-\frac{12000000000000000}{14141327413103869}$$

Whakaoti mō θ

$$\theta =\frac{1285575219373079f_{0}}{2000000000000000}+\frac{6}{11}$$