Tīpoka ki ngā ihirangi matua
Kimi Pārōnaki e ai ki Σ_3
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Aromātai
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Tohaina

\frac{4}{15}Σ_{3}^{1-1}
Ko te pārōnaki o ax^{n} ko nax^{n-1}.
\frac{4}{15}Σ_{3}^{0}
Tango 1 mai i 1.
\frac{4}{15}\times 1
Mō tētahi kupu t mahue te 0, t^{0}=1.
\frac{4}{15}
Mō tētahi kupu t, t\times 1=t me 1t=t.