Whakaoti i te sqrt{x-5}=sqrt{2x-7}

$$\sqrt{ x-5 } = \sqrt{ 2x-7 }$$

Whakaoti mō x (complex solution)

$$x=2$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{x-5}\right)^{2}=\left(\sqrt{2x-7}\right)^{2}$$

Tātaihia te \sqrt{x-5} mā te pū o 2, kia riro ko x-5.

$$x-5=\left(\sqrt{2x-7}\right)^{2}$$

Tātaihia te \sqrt{2x-7} mā te pū o 2, kia riro ko 2x-7.

$$x-5=2x-7$$

Tangohia te 2x mai i ngā taha e rua.

$$x-5-2x=-7$$

Pahekotia te x me -2x, ka -x.

$$-x-5=-7$$

Me tāpiri te 5 ki ngā taha e rua.

$$-x=-7+5$$

Tāpirihia te -7 ki te 5, ka -2.

$$-x=-2$$

Me whakarea ngā taha e rua ki te -1.

$$x=2$$

Whakakapia te 2 mō te x i te whārite \sqrt{x-5}=\sqrt{2x-7}.

$$\sqrt{2-5}=\sqrt{2\times 2-7}$$

Whakarūnātia. Ko te uara x=2 kua ngata te whārite.

$$i\times 3^{\frac{1}{2}}=i\times 3^{\frac{1}{2}}$$

Ko te whārite \sqrt{x-5}=\sqrt{2x-7} he rongoā ahurei.

$$x=2$$