Whakaoti i te sqrt{x}+sqrt{x}=4

$$\sqrt{ x } + \sqrt{ x } =4$$

Whakaoti mō x

$$x=4$$

Ngā Upane Otinga

Me tango \sqrt{x} mai i ngā taha e rua o te whārite.

$$\sqrt{x}=4-\sqrt{x}$$

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{x}\right)^{2}=\left(4-\sqrt{x}\right)^{2}$$

Tātaihia te \sqrt{x} mā te pū o 2, kia riro ko x.

$$x=\left(4-\sqrt{x}\right)^{2}$$

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(4-\sqrt{x}\right)^{2}.

$$x=16-8\sqrt{x}+\left(\sqrt{x}\right)^{2}$$

Tātaihia te \sqrt{x} mā te pū o 2, kia riro ko x.

$$x=16-8\sqrt{x}+x$$

Me tāpiri te 8\sqrt{x} ki ngā taha e rua.

$$x+8\sqrt{x}=16+x$$

Tangohia te x mai i ngā taha e rua.

$$x+8\sqrt{x}-x=16$$

Pahekotia te x me -x, ka 0.

$$8\sqrt{x}=16$$

Whakawehea ngā taha e rua ki te 8.

$$\sqrt{x}=\frac{16}{8}$$

Whakawehea te 16 ki te 8, kia riro ko 2.

$$\sqrt{x}=2$$

Pūruatia ngā taha e rua o te whārite.

$$x=4$$

Whakakapia te 4 mō te x i te whārite \sqrt{x}+\sqrt{x}=4.

$$\sqrt{4}+\sqrt{4}=4$$

Whakarūnātia. Ko te uara x=4 kua ngata te whārite.

$$4=4$$

Ko te whārite \sqrt{x}=-\sqrt{x}+4 he rongoā ahurei.

$$x=4$$