Whakaoti i te sqrt{5(x*3)}2-3x=0

$$\sqrt{ 5(x \times 3) } 2-3x = 0$$

Whakaoti mō x

$$x = \frac{20}{3} = 6\frac{2}{3} \approx 6.666666667$$

$$x=0$$

Ngā Upane Otinga

Me tango -3x mai i ngā taha e rua o te whārite.

$$2\sqrt{5x\times 3}=3x$$

Whakareatia te 5 ki te 3, ka 15.

$$2\sqrt{15x}=3x$$

Pūruatia ngā taha e rua o te whārite.

$$\left(2\sqrt{15x}\right)^{2}=\left(3x\right)^{2}$$

Whakarohaina te \left(2\sqrt{15x}\right)^{2}.

$$2^{2}\left(\sqrt{15x}\right)^{2}=\left(3x\right)^{2}$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$4\left(\sqrt{15x}\right)^{2}=\left(3x\right)^{2}$$

Tātaihia te \sqrt{15x} mā te pū o 2, kia riro ko 15x.

$$4\times 15x=\left(3x\right)^{2}$$

Whakareatia te 4 ki te 15, ka 60.

$$60x=\left(3x\right)^{2}$$

Whakarohaina te \left(3x\right)^{2}.

$$60x=3^{2}x^{2}$$

Tātaihia te 3 mā te pū o 2, kia riro ko 9.

$$60x=9x^{2}$$

Tangohia te 9x^{2} mai i ngā taha e rua.

$$60x-9x^{2}=0$$

Tauwehea te x.

$$x\left(60-9x\right)=0$$

Hei kimi otinga whārite, me whakaoti te x=0 me te 60-9x=0.

$$x=0 x=\frac{20}{3}$$

Whakakapia te 0 mō te x i te whārite 2\sqrt{5x\times 3}-3x=0.

$$2\sqrt{5\times 0\times 3}-3\times 0=0$$

Whakarūnātia. Ko te uara x=0 kua ngata te whārite.

$$0=0$$

Whakakapia te \frac{20}{3} mō te x i te whārite 2\sqrt{5x\times 3}-3x=0.

$$2\sqrt{5\times \frac{20}{3}\times 3}-3\times \frac{20}{3}=0$$

Whakarūnātia. Ko te uara x=\frac{20}{3} kua ngata te whārite.

$$0=0$$

Rārangihia ngā rongoā katoa o 2\sqrt{15x}=3x.

$$x=0 x=\frac{20}{3}$$