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\left(\sqrt{3x^{2}+7x-4}\right)^{2}=\left(-x\right)^{2}
Pūruatia ngā taha e rua o te whārite.
3x^{2}+7x-4=\left(-x\right)^{2}
Tātaihia te \sqrt{3x^{2}+7x-4} mā te pū o 2, kia riro ko 3x^{2}+7x-4.
3x^{2}+7x-4=x^{2}
Tātaihia te -x mā te pū o 2, kia riro ko x^{2}.
3x^{2}+7x-4-x^{2}=0
Tangohia te x^{2} mai i ngā taha e rua.
2x^{2}+7x-4=0
Pahekotia te 3x^{2} me -x^{2}, ka 2x^{2}.
a+b=7 ab=2\left(-4\right)=-8
Hei whakaoti i te whārite, whakatauwehea te taha mauī mā te whakarōpū. Tuatahi, me tuhi anō te taha mauī hei 2x^{2}+ax+bx-4. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.
-1,8 -2,4
I te mea kua tōraro te ab, he tauaro ngā tohu o a me b. I te mea kua tōrunga te a+b, he nui ake te uara pū o te tau tōrunga i tō te tōraro. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua -8.
-1+8=7 -2+4=2
Tātaihia te tapeke mō ia takirua.
a=-1 b=8
Ko te otinga te takirua ka hoatu i te tapeke 7.
\left(2x^{2}-x\right)+\left(8x-4\right)
Tuhia anō te 2x^{2}+7x-4 hei \left(2x^{2}-x\right)+\left(8x-4\right).
x\left(2x-1\right)+4\left(2x-1\right)
Tauwehea te x i te tuatahi me te 4 i te rōpū tuarua.
\left(2x-1\right)\left(x+4\right)
Whakatauwehea atu te kīanga pātahi 2x-1 mā te whakamahi i te āhuatanga tātai tohatoha.
x=\frac{1}{2} x=-4
Hei kimi otinga whārite, me whakaoti te 2x-1=0 me te x+4=0.
\sqrt{3\times \left(\frac{1}{2}\right)^{2}+7\times \frac{1}{2}-4}=-\frac{1}{2}
Whakakapia te \frac{1}{2} mō te x i te whārite \sqrt{3x^{2}+7x-4}=-x.
\frac{1}{2}=-\frac{1}{2}
Whakarūnātia. Ko te uara x=\frac{1}{2} kāore e ngata ana ki te whārite nā te mea e rerekē ngā tohu o te taha maui me te taha katau.
\sqrt{3\left(-4\right)^{2}+7\left(-4\right)-4}=-\left(-4\right)
Whakakapia te -4 mō te x i te whārite \sqrt{3x^{2}+7x-4}=-x.
4=4
Whakarūnātia. Ko te uara x=-4 kua ngata te whārite.
x=-4
Ko te whārite \sqrt{3x^{2}+7x-4}=-x he rongoā ahurei.