Whakaoti i te sqrt{3}(x+1)=x-1

$$\sqrt{ 3 } (x+1)=x-1$$

Whakaoti mō x

$$x=-\sqrt{3}-2\approx -3.732050808$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \sqrt{3} ki te x+1.

$$\sqrt{3}x+\sqrt{3}=x-1$$

Tangohia te x mai i ngā taha e rua.

$$\sqrt{3}x+\sqrt{3}-x=-1$$

Tangohia te \sqrt{3} mai i ngā taha e rua.

$$\sqrt{3}x-x=-1-\sqrt{3}$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(\sqrt{3}-1\right)x=-1-\sqrt{3}$$

He hanga arowhānui tō te whārite.

$$\left(\sqrt{3}-1\right)x=-\sqrt{3}-1$$

Whakawehea ngā taha e rua ki te \sqrt{3}-1.

$$\frac{\left(\sqrt{3}-1\right)x}{\sqrt{3}-1}=\frac{-\sqrt{3}-1}{\sqrt{3}-1}$$

Mā te whakawehe ki te \sqrt{3}-1 ka wetekia te whakareanga ki te \sqrt{3}-1.

$$x=\frac{-\sqrt{3}-1}{\sqrt{3}-1}$$

Whakawehe -1-\sqrt{3} ki te \sqrt{3}-1.

$$x=-\sqrt{3}-2$$