Whakaoti i te sqrt{-2^2}=left|-1right|+1/9*-3^2+sqrt[3]{-8}

$$\sqrt{ { -2 }^{ 2 } } = \left| -1 \right| + \frac{ 1 }{ 9 } \times { -3 }^{ 2 } + \sqrt[ 3 ]{ -8 }$$

Manatoko

Ngā Upane Otinga

Tātaihia te -2 mā te pū o 2, kia riro ko 4.

$$\sqrt{4}=|-1|+\frac{1}{9}\left(-3\right)^{2}+\sqrt[3]{-8}$$

Tātaitia te pūtakerua o 4 kia tae ki 2.

$$2=|-1|+\frac{1}{9}\left(-3\right)^{2}+\sqrt[3]{-8}$$

Ko te uara pū o tētahi tau tūturu a ko a ina a\geq 0, ko -a rānei ina a<0. Ko te uara pū o -1 ko 1.

$$2=1+\frac{1}{9}\left(-3\right)^{2}+\sqrt[3]{-8}$$

Tātaihia te -3 mā te pū o 2, kia riro ko 9.

$$2=1+\frac{1}{9}\times 9+\sqrt[3]{-8}$$

Whakareatia te \frac{1}{9} ki te 9, ka 1.

$$2=1+1+\sqrt[3]{-8}$$

Tāpirihia te 1 ki te 1, ka 2.

$$2=2+\sqrt[3]{-8}$$

Tātaitia te \sqrt[3]{-8} kia tae ki -2.

$$2=2-2$$

Tangohia te 2 i te 2, ka 0.

$$2=0$$

Whakatauritea te 2 me te 0.

$$\text{false}$$