Whakaoti i te sqrt[3]{9}x=sqrt{3x}

$$\sqrt[3]{ 9 } x= \sqrt{ 3x }$$

Whakaoti mō x

$$x=\frac{3^{\frac{2}{3}}}{3}\approx 0.693361274$$

$$x=0$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt[3]{9}x\right)^{2}=\left(\sqrt{3x}\right)^{2}$$

Whakarohaina te \left(\sqrt[3]{9}x\right)^{2}.

$$\left(\sqrt[3]{9}\right)^{2}x^{2}=\left(\sqrt{3x}\right)^{2}$$

Tātaihia te \sqrt{3x} mā te pū o 2, kia riro ko 3x.

$$\left(\sqrt[3]{9}\right)^{2}x^{2}=3x$$

Tangohia te 3x mai i ngā taha e rua.

$$\left(\sqrt[3]{9}\right)^{2}x^{2}-3x=0$$

Tauwehea te x.

$$x\left(\left(\sqrt[3]{9}\right)^{2}x-3\right)=0$$

Hei kimi otinga whārite, me whakaoti te x=0 me te \left(\sqrt[3]{9}\right)^{2}x-3=0.

$$x=0 x=\frac{3}{\left(\sqrt[3]{9}\right)^{2}}$$

Whakakapia te 0 mō te x i te whārite \sqrt[3]{9}x=\sqrt{3x}.

$$\sqrt[3]{9}\times 0=\sqrt{3\times 0}$$

Whakarūnātia. Ko te uara x=0 kua ngata te whārite.

$$0=0$$

Whakakapia te \frac{3}{\left(\sqrt[3]{9}\right)^{2}} mō te x i te whārite \sqrt[3]{9}x=\sqrt{3x}.

$$\sqrt[3]{9}\times \frac{3}{\left(\sqrt[3]{9}\right)^{2}}=\sqrt{3\times \frac{3}{\left(\sqrt[3]{9}\right)^{2}}}$$

Whakarūnātia. Ko te uara x=\frac{3}{\left(\sqrt[3]{9}\right)^{2}} kua ngata te whārite.

$$3\times 9^{-\frac{1}{3}}=3\times 9^{-\frac{1}{3}}$$

Rārangihia ngā rongoā katoa o \sqrt[3]{9}x=\sqrt{3x}.

$$x=0 x=\frac{3}{\left(\sqrt[3]{9}\right)^{2}}$$