Whakaoti i te sqrt[4]{1/81}+(2/3)^-1-0002*10^3

$$\sqrt[ 4 ] { \frac { 1 } { 81 } } + ( \frac { 2 } { 3 } ) ^ { - 1 } - 0002 \times 10 ^ { 3 }$$

Aromātai

$$\frac{11}{6}\approx 1.833333333$$

Ngā Upane Otinga

Tātaitia te \sqrt[4]{\frac{1}{81}} kia tae ki \frac{1}{3}.

$$\frac{1}{3}+\left(\frac{2}{3}\right)^{-1}-0\times 0\times 0\times 2\times 10^{3}$$

Tātaihia te \frac{2}{3} mā te pū o -1, kia riro ko \frac{3}{2}.

$$\frac{1}{3}+\frac{3}{2}-0\times 0\times 0\times 2\times 10^{3}$$

Tāpirihia te \frac{1}{3} ki te \frac{3}{2}, ka \frac{11}{6}.

$$\frac{11}{6}-0\times 0\times 0\times 2\times 10^{3}$$

Whakareatia te 0 ki te 0, ka 0.

$$\frac{11}{6}-0\times 0\times 2\times 10^{3}$$

Whakareatia te 0 ki te 0, ka 0.

$$\frac{11}{6}-0\times 2\times 10^{3}$$

Whakareatia te 0 ki te 2, ka 0.

$$\frac{11}{6}-0\times 10^{3}$$

Tātaihia te 10 mā te pū o 3, kia riro ko 1000.

$$\frac{11}{6}-0\times 1000$$

Whakareatia te 0 ki te 1000, ka 0.

$$\frac{11}{6}-0$$

Tangohia te 0 i te \frac{11}{6}, ka \frac{11}{6}.

$$\frac{11}{6}$$

Tauwehe

$$\frac{11}{2 \cdot 3} = 1\frac{5}{6} = 1.8333333333333333$$