Whakaoti i te sqrt{x}=x

$$\sqrt { x } = x$$

Whakaoti mō x

$$x=0$$

$$x=1$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{x}\right)^{2}=x^{2}$$

Tātaihia te \sqrt{x} mā te pū o 2, kia riro ko x.

$$x=x^{2}$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x-x^{2}=0$$

Tauwehea te x.

$$x\left(1-x\right)=0$$

Hei kimi otinga whārite, me whakaoti te x=0 me te 1-x=0.

$$x=0 x=1$$

Whakakapia te 0 mō te x i te whārite \sqrt{x}=x.

$$\sqrt{0}=0$$

Whakarūnātia. Ko te uara x=0 kua ngata te whārite.

$$0=0$$

Whakakapia te 1 mō te x i te whārite \sqrt{x}=x.

$$\sqrt{1}=1$$

Whakarūnātia. Ko te uara x=1 kua ngata te whārite.

$$1=1$$

Rārangihia ngā rongoā katoa o \sqrt{x}=x.

$$x=0 x=1$$