Whakaoti i te sqrt{x}=-x

$$\sqrt { x } = - x$$

Whakaoti mō x

$$x=0$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{x}\right)^{2}=\left(-x\right)^{2}$$

Tātaihia te \sqrt{x} mā te pū o 2, kia riro ko x.

$$x=\left(-x\right)^{2}$$

Tātaihia te -x mā te pū o 2, kia riro ko x^{2}.

$$x=x^{2}$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x-x^{2}=0$$

Tauwehea te x.

$$x\left(1-x\right)=0$$

Hei kimi otinga whārite, me whakaoti te x=0 me te 1-x=0.

$$x=0 x=1$$

Whakakapia te 0 mō te x i te whārite \sqrt{x}=-x.

$$\sqrt{0}=0$$

Whakarūnātia. Ko te uara x=0 kua ngata te whārite.

$$0=0$$

Whakakapia te 1 mō te x i te whārite \sqrt{x}=-x.

$$\sqrt{1}=-1$$

Whakarūnātia. Ko te uara x=1 kāore e ngata ana ki te whārite nā te mea e rerekē ngā tohu o te taha maui me te taha katau.

$$1=-1$$

Ko te whārite \sqrt{x}=-x he rongoā ahurei.

$$x=0$$